How large is the infinity in C language?

I found that while using Goolge's OR-Tools

// Create the mip solver with the SCIP backend.
  std::unique_ptr<MPSolver> solver(MPSolver::CreateSolver("SCIP"));
  if (!solver) {
    LOG(WARNING) << "SCIP solver unavailable.";
    return;
  }

  const double infinity = solver->infinity();

In here, I was curious about how large is solver->infinity()? So I found its clarify.

static double infinity() { return std::numeric_limits<double>::infinity(); }

Now, we continue, go deeper:

static _GLIBCXX_CONSTEXPR double
infinity() _GLIBCXX_USE_NOEXCEPT { return __builtin_huge_val(); }

this is in /usr/include/c++/12/limits

Now we Continue to see what is __builtin_huge_val():

#define __builtin_huge_val() __cowchild_cast<double>(0x7ff0000000000000)

I found this in /usr/include/cuda/std/climits, it's obvious that OR-Tools will not call cuda, but the number seems to be same.

So, infinity = 0x7ff0000000000000 in hex, and 9,218,868,437,227,405,312 in dec.

That's funny :).